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A group of 48 students including John and Monica go on a field trip using 3 buses each of which has a 16 student capacity. Students are divided at random into groups of 16 each. Find the probability that John and Monica are not on the same bus.

If anyone can help me out that would be great. You don't have to give me the answer, I just don't know how to set this kind of problem up.
 
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if you asked me this 2 years ago, I would have been able to help you.

find the probability they are on the same bus and subtract that from one?

do you have to use that C thing.. like 48C16.. create a set.. oh, ive got it

Put them as a pair... then find the probability you choose that pair when assigning your students per bus.
 

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Its never lupus
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I have prob/stat right now. I'll try and figure it out.
 
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say John gets asigned to a bus. There's a 15/47 chance that the chick is gonna be on the same bus. there fore there's a 32/47 chance she wont be on the same bus.

this seems too simple though..
 

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Its never lupus
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say John gets asigned to a bus. There's a 15/47 chance that the chick is gonna be on the same bus. there fore there's a 32/47 chance she wont be on the same bus.

this seems too simple though..
Yea, but that does sound correct.
 

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I was saving that bacon
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Heh, im taking business stats right now. Just had a test over this, and I didnt do so hot. Maybe I should have looked over my notes instead of going to a concert the night before. Nah.
 
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